Step 1: Understanding the Concept:
We need to find the number of possible samples of size 3 from a population of size 4 without replacement.
Step 2: Key Formula or Approach:
The number of ways to choose \(n\) items from \(N\) items without replacement and without regard to order is given by combinations:
\[
\binom{N}{n} = \frac{N!}{n!(N-n)!}
\]
Step 3: Detailed Explanation:
Here, \(N = 4\), \(n = 3\):
\[
\binom{4}{3} = \frac{4!}{3! \cdot 1!} = 4
\]
So, there are 4 possible samples.
Step 4: Final Answer:
Therefore, option (B) is correct.