Question:

A signal bandlimited to \(5\,\text{kHz}\) must be sampled at a minimum rate of

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The Nyquist sampling rate is \[ \boxed{ f_s \ge 2f_{\max} } \] to avoid aliasing.
Updated On: Jul 14, 2026
  • \(5\,\text{kHz}\)
  • \(7.5\,\text{kHz}\)
  • \(10\,\text{kHz}\)
  • \(20\,\text{kHz}\)
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The Correct Option is C

Solution and Explanation

Step 1: Apply the Nyquist sampling theorem. According to the Nyquist theorem, \[ f_s \geq 2f_{\max}, \] where \[ f_{\max}=5\,\text{kHz}. \]

Step 2:
Calculate the minimum sampling frequency. \[ f_s=2\times5=10\,\text{kHz}. \] Hence, \[ \boxed{10\,\text{kHz}} \] Therefore, \[ \boxed{(C)} \] is the correct answer.
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