Question:
A shopkeeper allowed successive discounts of 12% and x% on every item. A customer paid ₹15048 for an item marked for ₹18000. Find the value of x.
A shopkeeper allowed successive discounts of 12% and x% on every item. A customer paid ₹15048 for an item marked for ₹18000. Find the value of x.
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Successive discounts multiply factors
Updated On: Apr 21, 2026
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The Correct Option is B
Solution and Explanation
Step 1: Apply first discount of 12%.
Price after 12% discount = \(18000 \times (1 - 0.12) = 18000 \times 0.88 = 15840\). Step 2: Apply second discount of x%.
Price after x% discount = \(15840 \times \left(1 - \frac{x}{100}\right) = 15048\). Step 3: Solve for the factor \(1 - \frac{x}{100}\).
\(1 - \frac{x}{100} = \frac{15048}{15840}\).
Divide numerator and denominator: \(15048 \div 15840 = 0.95\). Step 4: Solve for x.
\(1 - \frac{x}{100} = 0.95\)
\(\frac{x}{100} = 0.05\)
\(x = 5\).
Price after 12% discount = \(18000 \times (1 - 0.12) = 18000 \times 0.88 = 15840\). Step 2: Apply second discount of x%.
Price after x% discount = \(15840 \times \left(1 - \frac{x}{100}\right) = 15048\). Step 3: Solve for the factor \(1 - \frac{x}{100}\).
\(1 - \frac{x}{100} = \frac{15048}{15840}\).
Divide numerator and denominator: \(15048 \div 15840 = 0.95\). Step 4: Solve for x.
\(1 - \frac{x}{100} = 0.95\)
\(\frac{x}{100} = 0.05\)
\(x = 5\).
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