The quality factor (\( Q \)) of a series RLC circuit is given by: \[ Q = \frac{1}{R} \sqrt{\frac{L}{C}}, \] where:
\( R = 100 \, \Omega \),
\( L = 1 \, \text{H} \),
\( C = 6.25 \, \mu\text{F} = 6.25 \times 10^{-6} \, \text{F} \).
Substitute the values: \[ Q = \frac{1}{100} \sqrt{\frac{1}{6.25 \times 10^{-6}}}. \]
Simplify: \[ Q = \frac{1}{100} \sqrt{1.6 \times 10^5} = \frac{1}{100} \cdot 400 = 4. \]
Final Answer: The quality factor is: \[ \boxed{4}. \]

A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.