Question:
A sedimentation tank has a volume of \(1500~\mathrm{m^3}\) and a flow of \(3000~\mathrm{m^3/day}\). Detention time is
A sedimentation tank has a volume of \(1500~\mathrm{m^3}\) and a flow of \(3000~\mathrm{m^3/day}\). Detention time is
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Detention time:
\[
\boxed{
t=\frac{V}{Q}
}
\]
where \(V\) = tank volume and \(Q\) = flow rate.
Updated On: Jul 18, 2026
- 6 hours
- 12 hours
- 18 hours
- 24 hours
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The Correct Option is B
Solution and Explanation
Detention time is given by
\[
t=\frac{\text{Volume}}{\text{Flow}}
\]
Substituting the given values,
\[
t=\frac{1500}{3000}=0.5\ \text{day}
\]
Converting into hours,
\[
0.5\times24=12\ \text{hours}
\]
Hence,
\[
\boxed{12\ \text{hours}}
\]
Therefore,
\[
\boxed{(B)}
\]
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