Question:
A sand sample has a porosity of \(30\%\) and specific gravity of solids is \(2.6\). What is its degree of saturation at moisture content of \(4.94\%\)?
A sand sample has a porosity of \(30\%\) and specific gravity of solids is \(2.6\). What is its degree of saturation at moisture content of \(4.94\%\)?
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Remember the important soil relationship:
\[
\boxed{w=\frac{Se}{G}}
\]
and
\[
\boxed{e=\frac{n}{1-n}}.
\]
These two formulas are sufficient to solve most numerical problems involving water content and degree of saturation.
Updated On: Jul 23, 2026
- \(40\%\)
- \(35\%\)
- \(30\%\)
- \(25\%\)
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Concept:
The water content, void ratio and degree of saturation are related by
\[
\boxed{w=\frac{Se}{G}}
\]
where
\[
w=\text{Water content},\quad
S=\text{Degree of saturation},\quad
e=\text{Void ratio},\quad
G=\text{Specific gravity of solids}.
\]
Also,
\[
\boxed{e=\frac{n}{1-n}}
\]
where \(n\) is the porosity.
Step 1: Calculate the void ratio. Given, \[ n=30\%=0.30. \] Therefore, \[ e=\frac{0.30}{1-0.30} =\frac{0.30}{0.70} =0.4286. \]
Step 2: Calculate the degree of saturation. Given, \[ w=4.94\%=0.0494,\qquad G=2.6. \] Using \[ w=\frac{Se}{G}, \] \[ S=\frac{wG}{e} =\frac{0.0494\times2.6}{0.4286} \approx0.30. \] Hence, \[ S=30\%. \] Therefore, \[ \boxed{\text{Degree of saturation}=30\%.} \] Hence, the correct option is \[ \boxed{(C)\;30\%.} \]
Step 1: Calculate the void ratio. Given, \[ n=30\%=0.30. \] Therefore, \[ e=\frac{0.30}{1-0.30} =\frac{0.30}{0.70} =0.4286. \]
Step 2: Calculate the degree of saturation. Given, \[ w=4.94\%=0.0494,\qquad G=2.6. \] Using \[ w=\frac{Se}{G}, \] \[ S=\frac{wG}{e} =\frac{0.0494\times2.6}{0.4286} \approx0.30. \] Hence, \[ S=30\%. \] Therefore, \[ \boxed{\text{Degree of saturation}=30\%.} \] Hence, the correct option is \[ \boxed{(C)\;30\%.} \]
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