Question

A retailer has 900 kg of wheat, a part of which he sells at 10% loss and the remaining at a profit of 8%. Overall, he makes a profit of 6%, the quantity sold at profit is :

• A. 100 kg
• B. 450 kg
• C. 600 kg
• D. 800 kg

Answer 1

The Correct Option is D

Let's solve the problem using the given conditions. We have:

• Total quantity of wheat = 900 kg.
• Let the quantity sold at a profit of 8% be x kg.
• Then the quantity sold at a 10% loss will be (900 - x) kg.

We are given that the total profit percentage is 6%. Let's set up the equation to find x:

First, we calculate the overall gain:

• Cost price of the total wheat = 900 kg.
• Selling price of the quantity sold at 8% profit = (x) × (1 + 8/100) = 1.08x.
• Selling price of the quantity sold at 10% loss = (900 - x) × (1 - 10/100) = 0.9(900 - x).

The total selling price considering a 6% profit would be the cost price + 6% profit:

• Total selling price = 900 × (1 + 6/100) = 954.

Let's equate the sum of individual selling prices to the total selling price:

1.08x + 0.9(900 - x) = 954

Expanding and solving the equation:

1.08x + 810 - 0.9x = 954

0.18x = 144

x = 800

Therefore, the quantity sold at a profit of 8% is 800 kg.