Question:
A resistor has three colour bands: Orange, Red and Black from left to right respectively. The value of resistance is
A resistor has three colour bands: Orange, Red and Black from left to right respectively. The value of resistance is
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Remember the resistor colour code:
\[
\text{Black}=0,\;
\text{Brown}=1,\;
\text{Red}=2,\;
\text{Orange}=3,\;
\text{Yellow}=4,
\]
\[
\text{Green}=5,\;
\text{Blue}=6,\;
\text{Violet}=7,\;
\text{Grey}=8,\;
\text{White}=9.
\]
For a three-band resistor,
\[
\text{Resistance}
=
(\text{first two digits})\times10^{(\text{third band value})}.
\]
Updated On: Jul 9, 2026
- \(16\,\Omega\)
- \(32\,\Omega\)
- \(320\,\Omega\)
- \(160\,\Omega\) \bigskip
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The Correct Option is B
Solution and Explanation
Concept:
For a three-band resistor:
• First band \(\rightarrow\) First significant digit
• Second band \(\rightarrow\) Second significant digit
• Third band \(\rightarrow\) Multiplier The standard colour code is: \[ \text{Black}=0,\; \text{Brown}=1,\; \text{Red}=2,\; \text{Orange}=3. \]
Step 1: Identify the significant digits. First band: Orange \[ 3 \] Second band: Red \[ 2 \] Thus the first two digits form \[ 32. \]
Step 2: Determine the multiplier. Third band: Black \[ 10^0=1. \]
Step 3: Calculate the resistance. \[ R = 32\times1. \] \[ R = 32\,\Omega. \]
Step 4: Write the final answer. \[ \boxed{R=32\,\Omega} \] \[ \boxed{\text{Answer = (B)}} \]
• First band \(\rightarrow\) First significant digit
• Second band \(\rightarrow\) Second significant digit
• Third band \(\rightarrow\) Multiplier The standard colour code is: \[ \text{Black}=0,\; \text{Brown}=1,\; \text{Red}=2,\; \text{Orange}=3. \]
Step 1: Identify the significant digits. First band: Orange \[ 3 \] Second band: Red \[ 2 \] Thus the first two digits form \[ 32. \]
Step 2: Determine the multiplier. Third band: Black \[ 10^0=1. \]
Step 3: Calculate the resistance. \[ R = 32\times1. \] \[ R = 32\,\Omega. \]
Step 4: Write the final answer. \[ \boxed{R=32\,\Omega} \] \[ \boxed{\text{Answer = (B)}} \]
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