Question:
A real object is placed at distance $f$ in front of a convex mirror of focal length $f$. The image will be formed at a distance
A real object is placed at distance $f$ in front of a convex mirror of focal length $f$. The image will be formed at a distance
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Convex mirror always forms virtual image → positive $v$.
Updated On: Apr 24, 2026
- $2f$
- $\frac{f}{8}$
- $f$
- $\frac{f}{4}$
- $\frac{f}{2}$
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The Correct Option is
Solution and Explanation
Concept:
• Mirror formula: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]
Step 1: Sign convention
For convex mirror: \[ f>0,\quad u = -f \]
Step 2: Substitute
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{f} \] \[ \Rightarrow \frac{1}{v} = \frac{2}{f} \] \[ v = \frac{f}{2} \] Final Conclusion:
Option (E)
• Mirror formula: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]
Step 1: Sign convention
For convex mirror: \[ f>0,\quad u = -f \]
Step 2: Substitute
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{f} \] \[ \Rightarrow \frac{1}{v} = \frac{2}{f} \] \[ v = \frac{f}{2} \] Final Conclusion:
Option (E)
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