Step 1: Use the equation for the age of rocks.
The formula for calculating the age of rocks from an isochron plot is:
\[
\text{Age} = \frac{\ln(1 + \text{Slope})}{\lambda^{87}\text{Rb}}
\]
Given that the slope is 0.003, and \( \lambda^{87}\text{Rb} = 1.39 \times 10^{-11} \, \text{yr}^{-1} \):
\[
\text{Age} = \frac{\ln(1 + 0.003)}{1.39 \times 10^{-11}} = \frac{\ln(1.003)}{1.39 \times 10^{-11}}
\]
Step 2: Simplify the calculation.
Using \( \ln(1.003) \approx 0.002995 \):
\[
\text{Age} = \frac{0.002995}{1.39 \times 10^{-11}} = 2.16 \times 10^{8} \, \text{years} = 216.0 \, \text{Ma}
\]
Final Answer:
\[
\boxed{216.0}
\]