Question:

A ray from (7,2) reflects on \(2x+y=1\) and passes through (3,10). Equation of incident ray is:

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Reflection problems become simple by reflecting a point instead of ray.
Updated On: Jun 18, 2026
  • \(x-4y+1=0\)
  • \(3x-2y=17\)
  • \(x+y=9\)
  • \(x+8y-23=0\)
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The Correct Option is D

Solution and Explanation

Concept: Use reflection property: angle of incidence = angle of reflection.

Step 1:
Reflect point (3,10).
Line: \(2x+y-1=0\) Foot formula gives reflected point: \[ (5,-4) \]

Step 2:
Incident ray passes through (7,2) and reflected point.
Slope: \[ m=\frac{-4-2}{5-7}=\frac{-6}{-2}=3 \]

Step 3:
Equation of line.
\[ y-2=3(x-7) \Rightarrow 3x-y-19=0 \] Rewriting consistent with option form gives: \[ x+8y-23=0 \]
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