Question

A photon has energy \(6\text{ eV}\). Its frequency is approximately:

• A. \(1.45\times10^{15}\text{ Hz}\)
• B. \(6\times10^{15}\text{ Hz}\)
• C. \(9\times10^{14}\text{ Hz}\)
• D. \(3\times10^{8}\text{ Hz}\)

Hint:

Remember: \[ 1\text{ eV}=1.6\times10^{-19}\text{ J} \]

Answer 1

The Correct Option is A

Step 1: Use photon energy relation. \[ E=hf \] Given: \[ E=6\text{ eV} \] \[ 1\text{ eV}=1.6\times10^{-19}\text{ J} \] Thus: \[ E=9.6\times10^{-19}\text{ J} \]

Step 2: Calculate frequency. \[ f=\frac{E}{h} \] \[ f= \frac{9.6\times10^{-19}} {6.63\times10^{-34}} \] \[ f\approx1.45\times10^{15}\text{ Hz} \] Therefore: \[ \boxed{1.45\times10^{15}\text{ Hz}} \]