Question:
A person A sold an article to another person B at a profit of \(8\%\) and B sold the same article to another person C at \(12\%\) profit. The ratio of the S.P. of the two transactions is
A person A sold an article to another person B at a profit of \(8\%\) and B sold the same article to another person C at \(12\%\) profit. The ratio of the S.P. of the two transactions is
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In successive selling problems, the first selling price always becomes the next person's cost price.
Updated On: Jul 15, 2026
- \(11:14\)
- \(13:21\)
- \(25:28\)
- \(35:37\)
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The Correct Option is C
Solution and Explanation
Concept:
Selling price in the first transaction becomes the cost price in the second transaction.
Step 1: Assume original cost price.
Let original cost price be: \[ 100 \] A sells to B at \(8\%\) profit. So first selling price: \[ SP_1=108 \]
Step 2: Find second selling price.
For B, cost price becomes: \[ 108 \] B sells at \(12\%\) profit. So: \[ SP_2=108+\frac{12}{100}\times108 \] \[ =108+12.96 \] \[ =120.96 \]
Step 3: Find the ratio.
\[ SP_1:SP_2=108:120.96 \] Multiply by \(100\): \[ 10800:12096 \] Divide by \(432\): \[ 25:28 \] Thus, the ratio of the two selling prices is: \[ \boxed{25:28} \]
Step 1: Assume original cost price.
Let original cost price be: \[ 100 \] A sells to B at \(8\%\) profit. So first selling price: \[ SP_1=108 \]
Step 2: Find second selling price.
For B, cost price becomes: \[ 108 \] B sells at \(12\%\) profit. So: \[ SP_2=108+\frac{12}{100}\times108 \] \[ =108+12.96 \] \[ =120.96 \]
Step 3: Find the ratio.
\[ SP_1:SP_2=108:120.96 \] Multiply by \(100\): \[ 10800:12096 \] Divide by \(432\): \[ 25:28 \] Thus, the ratio of the two selling prices is: \[ \boxed{25:28} \]
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