Question:
A pair of adjacent coils has a mutual inductance of 80 mH. If the current in one coil changes from 10 A to 25 A in a time of 1.5 s, the change of flux linked with the other coil is:
A pair of adjacent coils has a mutual inductance of 80 mH. If the current in one coil changes from 10 A to 25 A in a time of 1.5 s, the change of flux linked with the other coil is:
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Remember, the flux linkage change due to mutual inductance can be calculated directly from the product of mutual inductance and the change in current.
Updated On: Mar 13, 2025
- \(0.6 { Wb}\)
- \(1.8 { Wb}\)
- \(1.2 { Wb}\)
- \(0.8 { Wb}\)
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The Correct Option is C
Solution and Explanation
Step 1: Convert mutual inductance to Henrys. Mutual inductance \( M = 80 { mH} = 80 \times 10^{-3} { H} \).
Step 2: Calculate the change in current. The current change \( \Delta I = 25 { A} - 10 { A} = 15 { A} \).
Step 3: Calculate the change in flux \( \Delta \Phi \) linked with the other coil. \[ \Delta \Phi = M \times \Delta I = 80 \times 10^{-3} { H} \times 15 { A} = 1.2 { Wb}. \]
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