“A” obtained by Ostwald’s method involving air oxidation of\( NH_3\), upon further air oxidation produces “B”. “B” on hydration forms an oxoacid of Nitrogen along with evolution of “A”. The oxoacid also produces “A” and gives positive brown ring test.
“A” obtained by Ostwald’s method involving air oxidation of\( NH_3\), upon further air oxidation produces “B”. “B” on hydration forms an oxoacid of Nitrogen along with evolution of “A”. The oxoacid also produces “A” and gives positive brown ring test.
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For questions involving industrial processes:
• Understand key steps in the process (e.g., oxidation, hydration, and product formation).
• Focus on intermediate and final products to identify properties and tests.
\(NO, NO_2\)
\(N_2O_3, NO_2\)
\(NO_2, N_2O_4\)
\(NO_2, N_2O_5\)
The Correct Option is A
Solution and Explanation
1.Ostwald Process: In the Ostwald process, ammonia (\(\text{NH}_3\)) is oxidized by air to form nitric oxide (\(\text{NO}\)):
\[4\text{NH}_3 + 5\text{O}_2 \xrightarrow{\text{Pt, 500$^\circ$C}} 4\text{NO} + 6\text{H}_2\text{O}.\]
Thus, “A” is NO.
2. Further Oxidation of NO: Nitric oxide (\(\text{NO}\)) reacts with oxygen to form nitrogen dioxide (\(\text{NO}_2\)):
\[2\text{NO} + \text{O}_2 \rightarrow 2\text{NO}_2.\]
Thus, “B” is NO\(_2\).
3. Hydration of NO\(_2\): Nitrogen dioxide (\(\text{NO}_2\)) reacts with water to form nitric acid (\(\text{HNO}_3\)) and nitric oxide (\(\text{NO}\)):
\[3\text{NO}_2 + \text{H}_2\text{O} \rightarrow 2\text{HNO}_3 + \text{NO}.\]
4. Properties of HNO\(_3\): Nitric acid is an oxoacid of nitrogen. It gives a positive brown ring test, confirming the presence of NO.
Final Answer: \((3)\) \(\text{NO, NO}_2\).
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