Question:
A man travels three-fifths of a distance AB at a speed 3a, and the remaining at a speed 2b. If he goes from B to A and returns at a speed 5c in the same time, then
A man travels three-fifths of a distance AB at a speed 3a, and the remaining at a speed 2b. If he goes from B to A and returns at a speed 5c in the same time, then
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Time = distance/speed; equate when total times are equal.
Updated On: Mar 24, 2026
- $\frac{1}{a} + \frac{1}{b} = \frac{1}{c}$
- $a + b = c$
- $\frac{1}{a} + \frac{1}{b} = \frac{2}{c}$
- None of these
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The Correct Option is A
Solution and Explanation
Forward time = $\frac{3d/5}{3a} + \frac{2d/5}{2b} = \frac{d}{5a} + \frac{d}{5b} = \frac{d}{5}(\frac{1}{a} + \frac{1}{b})$.
Return time = $\frac{d}{5c}$. Equal times → $\frac{1}{a} + \frac{1}{b} = \frac{1}{c}$.
Return time = $\frac{d}{5c}$. Equal times → $\frac{1}{a} + \frac{1}{b} = \frac{1}{c}$.
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