Question:
A man presents with hemoptysis, fever, and breathlessness. Microscopic analysis of bronchoalveolar lavage reveals septate hyphae with acute angle branching. Which fungal infection is most likely?
A man presents with hemoptysis, fever, and breathlessness. Microscopic analysis of bronchoalveolar lavage reveals septate hyphae with acute angle branching. Which fungal infection is most likely?
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Aspergillus = septate hyphae with acute angle branching. Mucor = broad aseptate hyphae with right angle branching.
Updated On: Aug 27, 2026
- Mucormycosis
- Histoplasmosis
- Aspergillosis
- Candidiasis
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The Correct Option is C
Solution and Explanation
Concept:
Aspergillus species show septate hyphae with acute angle branching, classically around 45 degrees. They can cause pulmonary disease with hemoptysis.
Step 1: Identify fungal morphology.
The microscopy shows: \[ \text{Septate hyphae + acute angle branching} \]
Step 2: Recall organism.
This morphology is characteristic of: \[ \textit{Aspergillus} \]
Step 3: Choose infection.
Therefore, the most likely fungal infection is: \[ \text{Aspergillosis} \]
Step 1: Identify fungal morphology.
The microscopy shows: \[ \text{Septate hyphae + acute angle branching} \]
Step 2: Recall organism.
This morphology is characteristic of: \[ \textit{Aspergillus} \]
Step 3: Choose infection.
Therefore, the most likely fungal infection is: \[ \text{Aspergillosis} \]
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