Question

A man left one-half of his property for his wife, one-third for his son and the remainder for his daughter. If the daughter's share was worth Rs. 45,000, how much money did the man leave?

• A. Rs. 245,000
• B. Rs. 260,000
• C. Rs. 270,000
• D. Rs. 275,000

Hint:

Always express fractional divisions of a whole amount using a common denominator before solving.

Answer 1

The Correct Option is C

Let the total property be \( x \).
The daughter's share is: \[ x - \left( \frac{x}{2} + \frac{x}{3} \right) \] \[ = x - \left( \frac{3x}{6} + \frac{2x}{6} \right) = x - \frac{5x}{6} = \frac{x}{6} \] Given \( \frac{x}{6} = 45000 \), solving for \( x \): \[ x = 45000 \times 6 = 270,000 \] Thus, the man left Rs. 270,000.