Step 1: Convert nanomoles to moles.
20 nanomoles = \(20 \times 10^{-9}\) moles.
Step 2: Convert solution volume.
200 $\mu$L = \(200 \times 10^{-6}\) L = \(2 \times 10^{-4}\) L.
Step 3: Concentration in mol/L.
\[
C = \frac{20 \times 10^{-9}}{2 \times 10^{-4}} = 1 \times 10^{-4}\, \text{mol/L}.
\]
Step 4: Convert to $\mu$M.
\(1 \times 10^{-4}\, \text{M} = 100\, \mu\text{M}\).
But careful: check calculation again —
\[
C = \frac{20 \times 10^{-9}}{2 \times 10^{-4}} = 1 \times 10^{-4}\, \text{M}.
\]
Since \(1\ \text{M} = 10^{6}\ \mu\text{M}\),
\[
1 \times 10^{-4}\, \text{M} = 100\, \mu\text{M}.
\]
Correction: The integer answer is \(100\ \mu\text{M}\).