Question:

A loop moves towards a stationary magnet at constant speed \(V\), resulting in an induced emf \(E\) within the loop. If the magnet also moves away from the loop at the same speed \(V\), the new induced emf in the loop is

Show Hint

Induced emf depends on the rate of change of magnetic flux, not on the individual motions of the magnet or loop. If the relative position between the magnet and loop remains unchanged, \[ \frac{d\Phi}{dt}=0 \] and hence no emf is induced.
Updated On: Jul 9, 2026
  • \(E\)
  • \(\dfrac{E}{2}\)
  • \(2E\)
  • \(0\) \bigskip
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Concept: According to Faraday's law, \[ \mathcal{E} = -\frac{d\Phi}{dt}, \] where \(\Phi\) is the magnetic flux linked with the loop. An induced emf is produced only when the magnetic flux through the loop changes with time.

Step 1:
Consider the initial situation. When the loop moves towards the stationary magnet with speed \(V\), \[ \frac{d\Phi}{dt}\neq 0. \] Hence an induced emf \[ \mathcal{E}=E \] is produced.

Step 2:
Consider the new situation. Now the loop moves towards the magnet with speed \(V\), while the magnet simultaneously moves away from the loop with speed \(V\). Therefore, the relative speed between the loop and the magnet is \[ V-V=0. \] Hence the separation between them remains constant.

Step 3:
Determine the change in magnetic flux. Since the distance between the loop and the magnet does not change, \[ \Phi=\text{constant}. \] Thus, \[ \frac{d\Phi}{dt}=0. \] Therefore, \[ \mathcal{E} = -\frac{d\Phi}{dt} = 0. \]

Step 4:
Write the final answer. \[ \boxed{\mathcal{E}=0} \] \[ \boxed{\text{Answer = (D)}} \]
Was this answer helpful?
0
0

Top AP EAPCET Physics Questions

View More Questions