Question:

A long solenoid has \(1000\) turns per meter and carries a current of \(2\,A\). The magnetic field inside the solenoid is: \[ (\mu_0 = 4\pi \times 10^{-7}\,TmA^{-1}) \]

Show Hint

For long solenoids: \[ B\propto nI \] Increasing turns or current increases magnetic field strength.
Updated On: May 25, 2026
  • \(8\pi \times 10^{-4}\,T\)
  • \(4\pi \times 10^{-4}\,T\)
  • \(2\pi \times 10^{-4}\,T\)
  • \(16\pi \times 10^{-4}\,T\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Concept: Magnetic field inside a long solenoid is: \[ B=\mu_0 n I \] where:
  • \(B\) = magnetic field
  • \(n\) = turns per unit length
  • \(I\) = current


Step 1:
Write the formula. \[ B=\mu_0 nI \]

Step 2:
Substitute values. \[ B= (4\pi \times 10^{-7}) \times1000 \times2 \] \[ = 8\pi \times10^{-4}\,T \]

Step 3:
Final answer. \[ \boxed{ 8\pi \times10^{-4}\,T } \]
Was this answer helpful?
0
0