Question:

A KCl solution of conductivity \(0.14\ \mathrm{S\ m^{-1}}\) shows a resistance of \(4.19\ \Omega\) in a conductivity cell. If the same cell is filled with an HCl solution, the resistance drops to \(1.03\ \Omega\). The conductivity of the HCl solution is ____________ \(\times 10^{-2}\ \mathrm{S\ m^{-1}}\). (Round off to the Nearest Integer).

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The cell constant (conductivity × resistance) is the same for both solutions.
Updated On: Nov 4, 2026
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Correct Answer: 57

Solution and Explanation

Cell constant \(G^* = \kappa R = 0.14 \times 4.19 = 0.5866\ \mathrm{m^{-1}}\).
For HCl: \(\kappa = G^*/R = 0.5866/1.03 = 0.5695\ \mathrm{S\ m^{-1}} = 56.95\times 10^{-2}\ \mathrm{S\ m^{-1}}\).
Rounded to the nearest integer = 57.
Answer: 57
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