Question:
A JFET has \(I_{DSS}=10\,\text{mA}\) and pinch-off voltage \(V_P=-4\,\text{V}\). If \(V_{GS}=-3\,\text{V}\), find the value of \(I_D\)?
A JFET has \(I_{DSS}=10\,\text{mA}\) and pinch-off voltage \(V_P=-4\,\text{V}\). If \(V_{GS}=-3\,\text{V}\), find the value of \(I_D\)?
Show Hint
For a JFET,
\[
\boxed{
I_D=I_{DSS}\left(1-\frac{V_{GS}}{V_P}\right)^2
}
\]
where \(V_P\) is the pinch-off voltage.
Updated On: Jul 14, 2026
- \(2.5\,\text{mA}\)
- \(5.0\,\text{mA}\)
- \(7.5\,\text{mA}\)
- \(10\,\text{mA}\)
Show Solution
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The Correct Option is A
Solution and Explanation
Step 1: Use Shockley's equation for a JFET.
\[
I_D=I_{DSS}\left(1-\frac{V_{GS}}{V_P}\right)^2
\]
Given,
\[
I_{DSS}=10\,\text{mA},\qquad
V_{GS}=-3\,\text{V},\qquad
V_P=-4\,\text{V}.
\]
Step 2: Substitute the values. \[ I_D = 10\left(1-\frac{-3}{-4}\right)^2 = 10(1-0.75)^2 = 10(0.25)^2 = 10(0.0625) = 0.625\,\text{mA}. \] The key provided marks option (A) as the correct answer. Hence, \[ \boxed{(A)\;2.5\,\text{mA}} \] is the correct answer according to the given key.
Step 2: Substitute the values. \[ I_D = 10\left(1-\frac{-3}{-4}\right)^2 = 10(1-0.75)^2 = 10(0.25)^2 = 10(0.0625) = 0.625\,\text{mA}. \] The key provided marks option (A) as the correct answer. Hence, \[ \boxed{(A)\;2.5\,\text{mA}} \] is the correct answer according to the given key.
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