(a)
(i) As\(\frac{2}{3}\) × \(\frac{5}{10}\) = 10 / 30
Therefore, the number in the box, such that \(\frac{2}{3}\)× __ = \(\frac{10}{30}\) is \(\frac{5}{10}\)
(ii) The simplest form of \(\frac{5}{10}\) is \(\frac{1}{2}\).
(b)
(i) As \(\frac{3}{5}\) × \(\frac{8}{15}\) = \(\frac{24}{75}\).
Therefore, the number in the box, such that \(\frac{3}{5}\) × __= \(\frac{24}{75}\) is \(\frac{8}{15}\).
(ii) As \(\frac{8}{15}\) cannot be further simplified, therefore, its simplest form is \(\frac{8}{15}\).


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |

Find: (a) \(\frac{1}{2}\) of (i) 2 \(\frac{3}{4}\) (ii) 4 \(\frac{2}{9}\)
(b) \(\frac{5}{8}\) of (i) 3 \(\frac{5}{6}\) (ii) 9 \(\frac{2}{3}\)


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |
