Question

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

Answer 1

Inner radius of hemispherical bowl = 5 cm 
Thickness of the bowl = 0.25 cm 
Outer radius (r) of hemispherical bowl = (5 + 0.25) cm = 5.25 cm 
Outer CSA of hemispherical bowl =\( 2\pi r^2\)
= 2 × \(\frac{22}{7} \) × 5.25 cm × 5.25 cm
= 173.25 cm²
Therefore, the outer curved surface area of the bowl is 173.25 cm² .