Step 1: Calculate the energy required to heat the water.
The specific heat capacity of water \( C \) is approximately \( 4.18 { J/g°C} \), and the mass of water heated per minute is \( 3000 { g} \) (since \( 1 { liter} \approx 1000 { g} \)). Energy required \( Q \) to heat the water: \[ Q = mC\Delta T = 3000 { g} \times 4.18 { J/g°C} \times (77 - 27) { °C} = 627000 { J}. \] Step 2: Calculate the mass of gas required.
Using the heat of combustion: \[ {Mass of gas} = \frac{Q}{{Heat of combustion}} = \frac{627000 { J}}{4.0 \times 10^4 { J/g}^{-1}} \approx 15.675 { g/min}. \] The answer is rounded or adjusted to \(16 { g/min}^{-1}\) to match the option provided, suggesting typical usage rates and efficiency considerations might lead to this value.
In the given circuit, the electric currents through $15\, \Omega$ and $6 \, \Omega$ respectively are

Find the least horizontal force \( P \) to start motion of any part of the system of three blocks resting upon one another as shown in the figure. The weights of blocks are \( A = 300 \, {N}, B = 100 \, {N}, C = 200 \, {N} \). The coefficient of friction between \( A \) and \( C \) is 0.3, between \( B \) and \( C \) is 0.2 and between \( C \) and the ground is 0.1.

A truck of mass 1200 kg moves over an inclined plane raising 1 in 20, with a speed of 18 kmph. The power of the engine is
(g = 10 m/s\(^{-2}\)):
A man of mass 70 kg jumps to a height of 0.8 m from the ground, then the momentum transferred by the ground to the man is
(g = 10 m/s\(^{-2}\)):