Question:

A gas absorbs 500 J heat and does 200 J work. Change in internal energy is:

Show Hint

Think of it like a bank account: 500 J is "deposited" (heat absorbed), and 200 J is "spent" (work done). The balance remaining in the account is the change in internal energy (300 J).
Updated On: Jun 3, 2026
  • 300 J
  • 500 J
  • 700 J
  • -300 J
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Concept: This problem is based on theFirst Law of Thermodynamics**, which is a statement of the law of conservation of energy. It relates the heat supplied to a system, the work done by the system, and the change in its internal energy.
• Formula: \( \Delta U = Q - W \)
• \( \Delta U \): Change in internal energy.
• \( Q \): Heat added to the system (Positive if absorbed, Negative if released).
• \( W \): Work done by the system (Positive if work is done by gas, Negative if work is done on gas).

Step 1:
Identifying the given values with sign conventions.
Heat absorbed by the gas (\( Q \)) = +500 J (since energy is entering the system).
Work done by the gas (\( W \)) = +200 J (since the system is doing the work on surroundings).

Step 2:
Applying the First Law of Thermodynamics.
Substitute the values into the formula: \[ \Delta U = Q - W \] \[ \Delta U = 500 \text{ J} - 200 \text{ J} \] \[ \Delta U = 300 \text{ J} \]

Step 3:
Conclusion.
The internal energy of the gas increases by 300 J. This energy is stored within the gas, typically manifesting as an increase in temperature.
Was this answer helpful?
0
0

Top AP EAPCET Physics Questions

View More Questions