Concept:
This problem is based on theFirst Law of Thermodynamics**, which is a statement of the law of conservation of energy. It relates the heat supplied to a system, the work done by the system, and the change in its internal energy.
• Formula: \( \Delta U = Q - W \)
• \( \Delta U \): Change in internal energy.
• \( Q \): Heat added to the system (Positive if absorbed, Negative if released).
• \( W \): Work done by the system (Positive if work is done by gas, Negative if work is done on gas).
Step 1: Identifying the given values with sign conventions.
Heat absorbed by the gas (\( Q \)) = +500 J (since energy is entering the system).
Work done by the gas (\( W \)) = +200 J (since the system is doing the work on surroundings).
Step 2: Applying the First Law of Thermodynamics.
Substitute the values into the formula:
\[
\Delta U = Q - W
\]
\[
\Delta U = 500 \text{ J} - 200 \text{ J}
\]
\[
\Delta U = 300 \text{ J}
\]
Step 3: Conclusion.
The internal energy of the gas increases by 300 J. This energy is stored within the gas, typically manifesting as an increase in temperature.