Question

A full-wave rectifier has a peak voltage of \(100\,\text{V}\). The average output voltage is

• A. \(31.8\,\text{V}\)
• B. \(50\,\text{V}\)
• C. \(63.7\,\text{V}\)
• D. \(70.7\,\text{V}\)

Hint:

For a full-wave rectifier, \[ \boxed{ V_{\text{avg}}=\frac{2V_m}{\pi}\approx0.637V_m. } \]

Answer 1

The Correct Option is C

Step 1: Use the average output voltage formula. For a full-wave rectifier, \[ V_{\text{avg}} = \frac{2V_m}{\pi}, \] where \(V_m\) is the peak voltage. Given, \[ V_m=100\,\text{V}. \]

Step 2: Calculate the average voltage. \[ V_{\text{avg}} = \frac{2\times100}{\pi} = \frac{200}{3.1416} \approx63.7\,\text{V}. \] Hence, \[ \boxed{63.7\,\text{V}} \] Therefore, \[ \boxed{(C)} \] is the correct answer.