Step 1: Define the set of digits.
The odd digits are: \(\{1, 3, 5, 7, 9\}\).
So there are 5 choices for each digit if considered independently.
Step 2: Condition for the first digit.
The number must be a 3-digit number. The first digit can be any odd digit (5 choices).
Step 3: Condition for the second digit.
The second digit must be odd, but not equal to the first digit.
So there are \(5 - 1 = 4\) choices.
Step 4: Condition for the third digit.
The third digit must be odd, but not equal to the second digit.
Again, there are \(4\) choices.
Step 5: Total count.
\[
\text{Total frabjous numbers} = 5 \times 4 \times 4 = 80
\]
Final Answer: \[ \boxed{80} \]
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Ankita has to climb 5 stairs starting at the ground, while respecting the following rules: 1. At any stage, Ankita can move either one or two stairs up. 2. At any stage, Ankita cannot move to a lower step. Let \(F(N)\) denote the number of possible ways in which Ankita can reach the \(N^{th}\) stair. For example, \(F(1) = 1\), \(F(2) = 2\), \(F(3) = 3\). The value of \(F(5)\) is \(\underline{\hspace{1cm}}\).
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