Question

A four level PAM has a input data rate of \(2400~bits/s\) then the symbol rate is

• A. \(600~symbols/s\)
• B. \(1200~symbols/s\)
• C. \(2400~symbols/s\)
• D. \(9600~symbols/s\)

Hint:

For M-ary signaling: \[ R_s=\frac{R_b}{\log_2M} \] Four-level PAM carries 2 bits per symbol.

Answer 1

The Correct Option is B

Concept: For an M-ary system, \[ R_b=R_s\log_2M \] where \[ R_b=\text{bit rate} \] \[ R_s=\text{symbol rate} \]

Step 1: Determine bits per symbol.
For four-level PAM, \[ M=4 \] \[ \log_2 4=2 \] Thus each symbol carries 2 bits.

Step 2: Compute symbol rate.
\[ R_s=\frac{R_b}{2} \] \[ R_s=\frac{2400}{2} \] \[ R_s=1200 \] symbols/s.

Step 3: Final Answer.
\[ \boxed{1200~symbols/s} \] Hence, \[ \boxed{\text{Correct Option (B)}} \]