Question:
A FDM system is used to multiplex 24 independent voice signals. SSB modulation is used for the transmission. Given that each voice signal is allotted a bandwidth of 4 kHz, calculate the overall transmission bandwidth of the channel?
A FDM system is used to multiplex 24 independent voice signals. SSB modulation is used for the transmission. Given that each voice signal is allotted a bandwidth of 4 kHz, calculate the overall transmission bandwidth of the channel?
Show Hint
For SSB transmission:
\[
\text{Channel Bandwidth}
=
\text{Message Bandwidth}
\]
Therefore,
\[
B_{Total}=N\times B_m
\]
Updated On: Jun 25, 2026
- \(6~kHz\)
- \(8~kHz\)
- \(96~kHz\)
- \(192~kHz\)
Show Solution
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The Correct Option is C
Solution and Explanation
Concept:
In Frequency Division Multiplexing (FDM), each signal occupies its own frequency slot.
For SSB modulation, only one sideband is transmitted.
Therefore, the required bandwidth is equal to the message bandwidth.
Step 1: Write the bandwidth of one channel.
Given, \[ B_m=4~kHz \] Since SSB is used, \[ B_{SSB}=4~kHz \]
Step 2: Calculate total bandwidth.
Number of channels \[ N=24 \] Hence, \[ B_T=N\times B_{SSB} \] \[ B_T=24\times4 \] \[ B_T=96~kHz \]
Step 3: Final Answer.
\[ \boxed{B_T=96~kHz} \] Hence, \[ \boxed{\text{Correct Option (C)}} \]
Step 1: Write the bandwidth of one channel.
Given, \[ B_m=4~kHz \] Since SSB is used, \[ B_{SSB}=4~kHz \]
Step 2: Calculate total bandwidth.
Number of channels \[ N=24 \] Hence, \[ B_T=N\times B_{SSB} \] \[ B_T=24\times4 \] \[ B_T=96~kHz \]
Step 3: Final Answer.
\[ \boxed{B_T=96~kHz} \] Hence, \[ \boxed{\text{Correct Option (C)}} \]
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