Question:
A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C. Let $v_P$, $v_q$ and $v_c$ be the magnitude of velocities of points P,Q and C respectively, then
A disc is rolling (without slipping) on a horizontal surface. C is its centre and Q and P are two points equidistant from C. Let $v_P$, $v_q$ and $v_c$ be the magnitude of velocities of points P,Q and C respectively, then
Updated On: May 4, 2024
- $v_Q > v_C > v_P$
- $v_Q < v_C < v_P$
- $v_Q=v_P,v_C=\frac{1}{2}v_P$
- $v_Q < v_C > v_P$
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The Correct Option is A
Solution and Explanation
In case of pure rolling bottom most point is the instantaneous centre of zero velocity.
Velocity of any point on the disc, $v=r?,$ where r is the distance of point from O.
$r_Q > r_C > r_P$
$\therefore v_Q > v_C > v_P$
Therefore, the correct option is (a).
Velocity of any point on the disc, $v=r?,$ where r is the distance of point from O.
$r_Q > r_C > r_P$
$\therefore v_Q > v_C > v_P$
Therefore, the correct option is (a).
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