Question:

A die is thrown 100 times. Getting an even number is considered a success. The variance of the number of successes is

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For binomial distribution: Variance = \(npq\).
Here \(p = \frac{1}{2}\) for even numbers on a die.
  • 20
  • 25
  • 30
  • 50
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
This is a binomial distribution problem.
Each throw is a trial with success probability \(p\).

Step 2: Key Formula or Approach:

Variance of binomial distribution = \(npq\).

Step 3: Detailed Explanation:

On a die, the probability of getting an even number (2, 4, 6) is \(p = \frac{3}{6} = 0.5\).
Number of trials \(n = 100\).
So \(q = 1 - p = 0.5\).
Variance = \(npq = 100 \times 0.5 \times 0.5 = 25\).
Thus, the variance is 25, which is option (B).
The standard deviation would be \(\sqrt{25} = 5\).
Binomial distribution is appropriate here because each throw is independent.
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