Question

A computer has a memory space of \( 2^{16} \) and word length of 24 bits. Each memory chip has 10 address lines and 8 data lines. Number of chips required is:

• A. 192
• B. 256
• C. 512
• D. 1024

Hint:

Compute required chips as: Total bits / Chip capacity (bits).

Answer 1

The Correct Option is A

Total memory = \( 2^{16} \times 24 \) bits Each chip = \( 2^{10} \times 8 \) bits \[ \text{Total bits} = 65536 \times 24 = 1,572,864\ \text{bits} \] \[ \text{Each chip stores} = 1024 \times 8 = 8192\ \text{bits} \] \[ \text{Chips needed} = \frac{1572864}{8192} = 192 \]