A chemist has 4 samples of artificial sweetener A, B, C and D. To identify these samples, he performed certain experiments and noted the following observations :
(i) A and D both form blue-violet colour with ninhydrin.
(ii) Lassaigne extract of C gives positive \(\mathrm{AgNO_3}\) test and negative \(\mathrm{Fe_4[Fe(CN)_6]_3}\) test.
(iii) Lassaigne extract of B and D gives positive sodium nitroprusside test
Based on these observations which option is correct ?
(i) A and D both form blue-violet colour with ninhydrin.
(ii) Lassaigne extract of C gives positive \(\mathrm{AgNO_3}\) test and negative \(\mathrm{Fe_4[Fe(CN)_6]_3}\) test.
(iii) Lassaigne extract of B and D gives positive sodium nitroprusside test
Based on these observations which option is correct ?
Show Hint
- A : Aspartame ; B : Alitame ; C : Saccharin ; D ; Sucralose
- A : Alitame ; B : Saccharin ; C : Aspartame ; D ; Sucralose
- A : Aspartame ; B : Saccharin ; C : Sucralose ; D ; Alitame
- A : Saccharin ; B : Alitame ; C : Sucralose ; D ; Aspartame
The Correct Option is C
Solution and Explanation
(ii) C gives a positive AgNO3 test (halogen present) but a negative Prussian blue test (no nitrogen): C is sucralose (chlorinated sugar, no N, no S).
(iii) A positive sodium nitroprusside test indicates sulphur: B and D contain S. Saccharin and alitame contain sulphur, while aspartame has none.
D is in both (i) and (iii), so D = alitame, hence A = aspartame, and B = saccharin.
Result: A : Aspartame; B : Saccharin; C : Sucralose; D : Alitame.
Answer: (3) A : Aspartame ; B : Saccharin ; C : Sucralose ; D ; Alitame
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