Question:
A CE amplifier has \(h_{fe}=100\) and load resistance \(R_L=2\,\text{k}\Omega\). The approximate low-frequency current gain is
A CE amplifier has \(h_{fe}=100\) and load resistance \(R_L=2\,\text{k}\Omega\). The approximate low-frequency current gain is
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For a CE amplifier,
\[
\boxed{
A_i \approx h_{fe}=\beta
}
\]
at low and mid frequencies.
Updated On: Jul 14, 2026
- \(2\)
- \(20\)
- \(100\)
- \(200\)
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The Correct Option is C
Solution and Explanation
Step 1: Recall the current gain of a CE amplifier.
For a common-emitter amplifier operating at low frequencies,
\[
A_i \approx h_{fe}.
\]
Given,
\[
h_{fe}=100.
\]
Step 2: Determine the current gain. The load resistance affects the voltage gain but has negligible effect on the current gain. Therefore, \[ A_i \approx 100. \] Hence, \[ \boxed{100} \] Therefore, \[ \boxed{(C)} \] is the correct answer.
Step 2: Determine the current gain. The load resistance affects the voltage gain but has negligible effect on the current gain. Therefore, \[ A_i \approx 100. \] Hence, \[ \boxed{100} \] Therefore, \[ \boxed{(C)} \] is the correct answer.
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