For motion on curved roads:
• Use the formula vmax = \(\sqrt{µgr}\) for safe turning.
• Ensure all values are in consistent units for accurate results.
13.4m/s
13m/s
22.4m/s
17m/s
1. Maximum Speed on a Curved Road: - The maximum speed of a vehicle on a curved road is given by:
\[v_\text{max} = \sqrt{\mu gr},\]
where \(\mu\) is the coefficient of friction, g is the acceleration due to gravity, and r is the radius of curvature.
2. Substitute the Values: - \(\mu = 0.34\), g = 10 m/s2, r = 50 m:
\[v_\text{max} = \sqrt{0.34 \times 10 \times 50} = \sqrt{170} \approx 13 \, \text{m/s}.\]
Final Answer: \(\boxed{13 \, \text{m/s}}\)

A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]