A bullet of 10 g leaves the barrel of gun with a velocity of 600 m/s. If the barrel of gun is 50 cm long and mass of gun is 3 kg, then value of impulse supplied to the gun will be :
Show Hint
{Impulse} is the product of force and the time during which the force acts. It is equal to the change in momentum of an object. Mathematically, \( J = F \cdot t = \Delta p \).
- 12 Ns
- 3 Ns
- 6 Ns
- 36 Ns
The Correct Option is C
Solution and Explanation
Impulse (\( J \)) is defined as the change in momentum of an object. It can be calculated using the formula: \[ J = \Delta p = m \cdot v \] where:
\( m \) is the mass of the bullet,
\( v \) is the velocity of the bullet.
Given: \[ m = 10 \, \text{g} = 0.01 \, \text{kg} \\ v = 600 \, \text{m/s} \] Substituting the values: \[ J = 0.01 \, \text{kg} \times 600 \, \text{m/s} = 6 \, \text{Ns} \] Therefore, the impulse supplied to the gun is \( 6 \, \text{Ns} \).
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