Question:

A bulk magnetic material has volume \[ 2\,\text{m}^3 \] and its magnetization is found to be \[ 2\,\text{A m}^{-1}. \] Then the magnetic moment of the bulk material is

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Remember: \[ \boxed{M=\frac{\text{Magnetic Moment}}{\text{Volume}}} \] Hence, \[ \boxed{\text{Magnetic Moment}=M\times V}. \] Units: \[ M \rightarrow \text{A m}^{-1}, \qquad m \rightarrow \text{A m}^2. \]
Updated On: Jul 29, 2026
  • \[ 1\,\text{A m}^2 \]
  • \[ 4\,\text{A m}^2 \]
  • \[ 2\,\text{A m}^2 \]
  • \[ 8\,\text{A m}^2 \]
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The Correct Option is B

Solution and Explanation

Concept: Magnetization is defined as the magnetic moment per unit volume: \[ M=\frac{m}{V}, \] where \[ M=\text{magnetization}, \qquad m=\text{magnetic moment}, \qquad V=\text{volume}. \]

Step 1: Write the given data. \[ M=2\,\text{A m}^{-1}, \] \[ V=2\,\text{m}^3. \]

Step 2: Calculate the magnetic moment. From \[ M=\frac{m}{V}, \] we get \[ m=MV. \] Substituting the values, \[ m=(2)(2). \] \[ m=4\,\text{A m}^2. \]

Step 3: Identify the correct option. \[ \boxed{m=4\,\text{A m}^2} \] Therefore, \[ \boxed{\text{Answer = (B)}} \]
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