Question:
A body starts from rest and accelerates uniformly at \(2\ \text{m/s}^2\). The distance covered in \(5\ \text{s}\) is:
A body starts from rest and accelerates uniformly at \(2\ \text{m/s}^2\). The distance covered in \(5\ \text{s}\) is:
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If a body starts from rest, then \(u=0\), and the formula becomes \(s=\frac{1}{2}at^2\).
Updated On: Jun 3, 2026
- \(10\ \text{m}\)
- \(20\ \text{m}\)
- \(25\ \text{m}\)
- \(50\ \text{m}\)
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The Correct Option is C
Solution and Explanation
Concept:
For uniformly accelerated motion, distance covered is given by: \(\displaystyle s=ut+\frac{1}{2}at^2\) where, \(u=\) initial velocity
\(a=\) acceleration
\(t=\) time
Step 1: Write the given values.
The body starts from rest, so: \(\displaystyle u=0\) Acceleration: \(\displaystyle a=2\ \text{m/s}^2\) Time: \(\displaystyle t=5\ \text{s}\)
Step 2: Apply the formula.
\(\displaystyle s=ut+\frac{1}{2}at^2\) \(\displaystyle s=(0)(5)+\frac{1}{2}(2)(5)^2\) \(\displaystyle s=0+1\times 25\) \(\displaystyle s=25\ \text{m}\)
Step 3: Final conclusion.
Hence, the distance covered is: \(\displaystyle \boxed{25\ \text{m}}\)
For uniformly accelerated motion, distance covered is given by: \(\displaystyle s=ut+\frac{1}{2}at^2\) where, \(u=\) initial velocity
\(a=\) acceleration
\(t=\) time
Step 1: Write the given values.
The body starts from rest, so: \(\displaystyle u=0\) Acceleration: \(\displaystyle a=2\ \text{m/s}^2\) Time: \(\displaystyle t=5\ \text{s}\)
Step 2: Apply the formula.
\(\displaystyle s=ut+\frac{1}{2}at^2\) \(\displaystyle s=(0)(5)+\frac{1}{2}(2)(5)^2\) \(\displaystyle s=0+1\times 25\) \(\displaystyle s=25\ \text{m}\)
Step 3: Final conclusion.
Hence, the distance covered is: \(\displaystyle \boxed{25\ \text{m}}\)
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