The correct option is (B) : 60 J
vi = 3(0)2 + 4 = 4 ≅ x = 0
vF = 3(2)2 + 4 = 16 ≅ x = 2
\(W=ΔK=\frac{1}{2}m(16^2-4^2)\)
\(=\frac{1}{2}\times\frac{1}{2}(256-16)=\frac{240}{4}\)
\(=60\ J\)

Potential energy (V) versus distance (x) is given by the graph. Rank various regions as per the magnitudes of the force (F) acting on a particle from high to low. 
A wire of uniform resistance \(\lambda\) \(\Omega\)/m is bent into a circle of radius r and another piece of wire with length 2r is connected between points A and B (ACB) as shown in figure. The equivalent resistance between points A and B is_______ \(\Omega\).

The correct sequence of reagents for the above conversion of X to Y is :
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