Question:
A body moves with uniform speed of \( 20 \text{ ms}^{-1} \) in a horizontal circle. What is the change in velocity after half revolution?
A body moves with uniform speed of \( 20 \text{ ms}^{-1} \) in a horizontal circle. What is the change in velocity after half revolution?
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In circular motion, for half a revolution, the change in velocity = 2 × speed.
Updated On: May 13, 2025
- \( 20 \text{ ms}^{-1} \)
- \( 10 \text{ ms}^{-1} \)
- \( 40 \text{ ms}^{-1} \)
- \( \frac{20}{\sqrt{2}} \text{ ms}^{-1} \)
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The Correct Option is C
Solution and Explanation
Speed is same, but after half revolution, direction reverses
Initial velocity = \( 20 \, \text{ms}^{-1} \), Final = \( -20 \, \text{ms}^{-1} \)
Change in velocity = \( |-20 - 20| = 40 \, \text{ms}^{-1} \)
Initial velocity = \( 20 \, \text{ms}^{-1} \), Final = \( -20 \, \text{ms}^{-1} \)
Change in velocity = \( |-20 - 20| = 40 \, \text{ms}^{-1} \)
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