A batsman was having 32 runs per innings as his average after the 15th innings. His average increased by 2 runs after the 16th inning. Then what was his score in the 16th inning?
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Use total runs before and after: new total minus old total gives the 16th innings score.
To solve the problem, we will use the concept of averages and simple arithmetic calculations. Let's go through the solution step-by-step:
Initially, the batsman had played 15 innings with an average of 32 runs per inning. Thus, the total runs scored in these 15 innings can be calculated as follows: \(Total\ Runs\ for\ 15\ innings = 15 \times 32 = 480\)
After the 16th inning, the batsman's average increased by 2 runs, making the new average 34 runs per inning. This new average is calculated based on 16 innings. \(New\ Total\ Runs\ for\ 16\ innings = 16 \times 34 = 544\)
To find out the score in the 16th inning, we subtract the total runs after 15 innings from the total runs after 16 innings: \(Score\ in\ 16th\ inning = 544 - 480 = 64\)
The batsman's score in the 16th inning was 64.
This confirms that the correct option is 64.
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Approach Solution -2
Step 1: Find the total runs from the first 15 innings.
The batsman's average after 15 innings is 32 runs. So his total runs from these innings is \(32 \times 15 = 480\).
Step 2: Find the new total after 16 innings.
His average goes up by 2 runs after the 16th innings, so the new average is \(32 + 2 = 34\). The total runs after 16 innings is \(34 \times 16 = 544\).
Step 3: Find the score in the 16th innings.
The score in the 16th innings is the difference between the two totals: \(544 - 480 = 64\).
Final Answer:
The batsman scored 64 runs in the 16th innings.
\[ \boxed{64} \]
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