Step 1: Use the formula for maximum height in vertical motion: \[ H = \frac{u^2}{2g} \] where \( u = 20 \, m/s \) and \( g = 10 \, m/s^2 \).
Step 2: Substitute the values: \[ H = \frac{20^2}{2 \times 10} = \frac{400}{20} = 20 \, m. \]
Step 3: Therefore, the maximum height reached by the ball is 20 meters.
A person climbs up a conveyor belt with a constant acceleration. The speed of the belt is \( \sqrt{\frac{g h}{6}} \) and the coefficient of friction is \( \frac{5}{3\sqrt{3}} \). The time taken by the person to reach from A to B with maximum possible acceleration is:
