A bag contains four balls. Two balls are drawn randomly and found them to be white. The probability that all the balls in the bag are white is
\(\frac{1}{2}\)
\(\frac{3}{5}\)
\(\frac{1}{4}\)
\(\frac{2}{3}\)
To solve this problem, we use conditional probability.
Let:
We need to find:
\( \Pr(A \mid B) \)
By definition of conditional probability:
\[ \Pr(A \mid B) = \frac{\Pr(A \cap B)}{\Pr(B)} \]
Step 1: Compute \( \Pr(A \cap B) \)
If all balls are white (event \(A\)), then drawing two white balls is certain:
\[ \Pr(B \mid A) = 1 \Rightarrow \Pr(A \cap B) = \Pr(A) \]
Step 2: Compute \( \Pr(B) \)
Using total probability:
\[ \Pr(B) = \Pr(B \mid A)\Pr(A) + \Pr(B \mid A^c)\Pr(A^c) \]
So:
\[ \Pr(B) = 1 \cdot \Pr(A) + \Pr(B \mid A^c)(1 - \Pr(A)) \]
Step 3: Conditional probability
\[ \Pr(A \mid B) = \frac{\Pr(A)}{\Pr(A) + \Pr(B \mid A^c)(1 - \Pr(A))} \]
Important observation:
Without additional information about the composition of the bag or the value of \(\Pr(A)\), the expression cannot be reduced to a numerical value.
Conclusion: The probability cannot be uniquely determined from the given information.
If 3 dice are thrown, the probability of getting 10 as the sum of the three numbers on the top faces is ?
Three similar urns \(A,B,C\) contain \(2\) red and \(3\) white balls; \(3\) red and \(2\) white balls; \(1\) red and \(4\) white balls, respectively. If a ball is selected at random from one of the urns is found to be red, then the probability that it is drawn from urn \(C\) is ?
. If a random variable X has the following probability distribution, then the mean of X is:
|
If three numbers are randomly selected from the set \( \{1,2,3,\dots,50\} \), then the probability that they are in arithmetic progression is:
Probability is defined as the extent to which an event is likely to happen. It is measured by the ratio of the favorable outcome to the total number of possible outcomes.
The set of possible results or outcomes in a trial is referred to as the sample space. For instance, when we flip a coin, the possible outcomes are heads or tails. On the other hand, when we roll a single die, the possible outcomes are 1, 2, 3, 4, 5, 6.
In a sample space, a sample point is one of the possible results. For instance, when using a deck of cards, as an outcome, a sample point would be the ace of spades or the queen of hearts.
When the results of a series of actions are always uncertain, this is referred to as a trial or an experiment. For Instance, choosing a card from a deck, tossing a coin, or rolling a die, the results are uncertain.
An event is a single outcome that happens as a result of a trial or experiment. For instance, getting a three on a die or an eight of clubs when selecting a card from a deck are happenings of certain events.
A possible outcome of a trial or experiment is referred to as a result of an outcome. For instance, tossing a coin could result in heads or tails. Here the possible outcomes are heads or tails. While the possible outcomes of dice thrown are 1, 2, 3, 4, 5, or 6.