Question:
A bag contains 4 five rupee coins, 3 two rupee coins and 3 one rupee coins. If 6 coins are drawn from the bag at random, what are the odds in favour of the draw yielding maximum amount?
A bag contains 4 five rupee coins, 3 two rupee coins and 3 one rupee coins. If 6 coins are drawn from the bag at random, what are the odds in favour of the draw yielding maximum amount?
Updated On: Jan 30, 2025
- 1 : 70
- 1 : 69
- 69 : 70
- 70 : 1
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The Correct Option is C
Solution and Explanation
Total number of coins in the bag = 4 + 3 + 3 = 10
If 6 coins are drawn from the bag at random, then the probability that the draw yields maximum amount is given by,
\(=\frac{4^{c4}\times3^{c2}}{10^{c6}}\)
\(=\frac{1\times3}{210}\)
\(=\frac{1}{70}\)
Odds in favour of the draw \(1-\frac{1}{70}=\frac{69}{70}\)
Hence, option C is the correct answer.The correct option is (C): 69 : 70
If 6 coins are drawn from the bag at random, then the probability that the draw yields maximum amount is given by,
\(=\frac{4^{c4}\times3^{c2}}{10^{c6}}\)
\(=\frac{1\times3}{210}\)
\(=\frac{1}{70}\)
Odds in favour of the draw \(1-\frac{1}{70}=\frac{69}{70}\)
Hence, option C is the correct answer.The correct option is (C): 69 : 70
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