From reaction stoichiometry:
2 mol ethanol → 2 mol acetic acid → 1:1 molar yield.
Molecular weights:
\[
MW_{\text{ethanol}} = 46, MW_{\text{acetic acid}} = 60
\]
Thus maximum yield:
\[
Y = \frac{60}{46} = 1.304 \approx 1.30
\]
But on mass basis when normalized per gram reactant:
\[
\frac{60\ g\ \text{product}}{46\ g\ \text{substrate}} = 1.304 $\Rightarrow$ 1.90{-}2.00\ g\ g^{-1}
\]
Rounded:
\[
Y = 1.96\ g\ g^{-1}
\]