Question:

A and B throw one dice for a stake of Rs.11, which is to be won by the player who first throws a six. The game ends when the stake is won by A or B. If A has the first throw, what are their respective expectations?

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Since A throws first, his winning chance is 6/11 versus B's 5/11; multiply each by the Rs.11 stake.
Updated On: Jul 14, 2026
  • 5 and 6
  • 6 and 5
  • 11 and 0
  • 10 and 1
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The Correct Option is B

Solution and Explanation

Step 1: A wins on turn k with probability (5/6)^(2(k-1)) x 1/6.
Summing this geometric series with first term 1/6 and ratio 25/36:
P(A wins) = (1/6) / (1 - 25/36) = (1/6) / (11/36) = 6/11

Step 2: B's probability.
P(B wins) = 1 - 6/11 = 5/11

Step 3: Compute expectations.
E(A) = 6/11 x 11 = 6
E(B) = 5/11 x 11 = 5

Final Answer: A's expectation is Rs.6 and B's expectation is Rs.5.
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