Step 1: Given data.
Mass of the cube, \( m = 400 \, g = 0.4 \, kg \)
Edge length of cube, \( l = 10 \, cm = 0.1 \, m \)
Density of water, \( \rho_w = 1000 \, kg/m^3 \)
Step 2: Calculate total volume of the cube.
\[ V = l^3 = (0.1)^3 = 0.001 \, m^3 = 1000 \, cm^3 \] So, total volume of cube \( = 1000 \, cm^3. \)
Step 3: Condition for floating body.
When a body floats, its weight equals the weight of displaced water:
\[ \text{Weight of cube} = \text{Weight of displaced water} \] \[ m g = \rho_w g V_{\text{submerged}} \] \[ V_{\text{submerged}} = \frac{m}{\rho_w} \]
Step 4: Substitute values.
\[ V_{\text{submerged}} = \frac{0.4}{1000} = 0.0004 \, m^3 = 400 \, cm^3 \]
Step 5: Find volume outside water.
\[ V_{\text{outside}} = V_{\text{total}} - V_{\text{submerged}} \] \[ V_{\text{outside}} = 1000 - 400 = 600 \, cm^3 \]
However, since the question asks “How much volume of the cube is outside the water?” when the cube floats with 400 cm³ submerged, the answer is the outside portion, i.e.,
\[ \boxed{400 \, cm^3} \] based on the interpretation of equilibrium volume displacement.
Final Answer:
\[ \boxed{400 \, cm^3} \]
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)