Question:
A \(1000\,\text{kg}\) car moves at \(20\,\text{m s}^{-1}\). The power required to maintain this speed against a resistive force of \(500\,\text{N}\) is
A \(1000\,\text{kg}\) car moves at \(20\,\text{m s}^{-1}\). The power required to maintain this speed against a resistive force of \(500\,\text{N}\) is
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For motion at constant speed,
\[
P=Fv.
\]
Here \(F\) is the force opposing the motion and \(v\) is the speed of the body.
Updated On: Jul 9, 2026
- \(5\,\text{kW}\)
- \(10\,\text{kW}\)
- \(20\,\text{kW}\)
\(50\,\text{kW}\)
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The Correct Option is B
Solution and Explanation
Concept:
Power required to maintain a constant speed against a resistive force is
\[
P=Fv,
\]
where \(F\) is the resistive force and \(v\) is the speed.
Step 1: Substitute the given values. \[ F=500\,\text{N} \] \[ v=20\,\text{m s}^{-1} \] Therefore, \[ P=500\times20. \] \[ P=10000\,\text{W}. \]
Step 2: Convert into kilowatts. \[ 10000\,\text{W} = 10\,\text{kW}. \]
Step 3: Write the final answer. \[ \boxed{P=10\,\text{kW}} \] \[ \boxed{\text{Answer = (B)}} \]
Step 1: Substitute the given values. \[ F=500\,\text{N} \] \[ v=20\,\text{m s}^{-1} \] Therefore, \[ P=500\times20. \] \[ P=10000\,\text{W}. \]
Step 2: Convert into kilowatts. \[ 10000\,\text{W} = 10\,\text{kW}. \]
Step 3: Write the final answer. \[ \boxed{P=10\,\text{kW}} \] \[ \boxed{\text{Answer = (B)}} \]
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